Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.5 Rational Expressions - R.5 Exercises - Page 53: 21

Answer

$\color{blue}{\dfrac{2x+4}{x}} $

Work Step by Step

Factor the numerator and the denominator then cancel the common factors to obtain: $\require{cancel} =\dfrac{4x(2x+4)}{4x(x)} \\=\dfrac{\cancel{4x}(2x+4)}{\cancel{4x}(x)} \\=\color{blue}{\dfrac{2x+4}{x}} $
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