Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.5 Rational Expressions - R.5 Exercises: 29

Answer

$\color{blue}{\dfrac{2m+3}{4m+3}}$

Work Step by Step

Factor the numerator and the denominator then cancel the common factors to obtain: $\require{cancel} =\dfrac{(4m-3)(2m+3)}{(4m-3)(4m+3)} \\=\dfrac{\cancel{(4m-3)}(2m+3)}{\cancel{(4m-3)}(4m+3)} \\=\color{blue}{\dfrac{2m+3}{4m+3}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.