Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.5 Rational Expressions - R.5 Exercises - Page 53: 34

Answer

$\color{blue}{\dfrac{12r^3}{5}}$

Work Step by Step

Use the rule $\dfrac{a}{b} \div \dfrac{c}{d} = \dfrac{a}{b} \times \dfrac{d}{c}$ to obtain: $\dfrac{8r^3}{6r} \times \dfrac{9r^3}{5r^2}$ Cancel common factors, then multiply to obtain: $\require{cancel} =\dfrac{\cancel{8}4\cancel{r^3}r^2}{\cancel{6}3\cancel{r}} \times \dfrac{9\cancel{r^3}r}{5\cancel{r^2}} \\=\dfrac{4r^2}{3} \times \dfrac{9r}{5} \\=\dfrac{4r^2}{\cancel{3}} \times \dfrac{\cancel{9}3r}{5} \\=\color{blue}{\dfrac{12r^3}{5}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.