Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.5 Rational Expressions - R.5 Exercises - Page 53: 24

Answer

$\color{blue}{\dfrac{8}{y+2}}$

Work Step by Step

Factor the numerator and the denominator then cancel the common factors to obtain: $\require{cancel} =\dfrac{-8(-1)(-4+y)}{(y+2)(y-4)} \\=\dfrac{8(y-4)}{(y+2)(y-4)} \\=\dfrac{8\cancel{(y-4)}}{(y+2)\cancel{(y-4)}} \\=\color{blue}{\dfrac{8}{y+2}}$
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