Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises - Page 33: 80

Answer

$81r^2-18rs+s^2-4$

Work Step by Step

Use the formula $(a+b)(a-b)=a^2-b^2$ and treat $9r-s$ as a single term, we have: $[(9r-s)+2][(9r-s)-2]=(9r-s)^2-2^2=81r^2-18rs+s^2-4$
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