Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises - Page 33: 52



Work Step by Step

First distribute the 3 located outside the first set of parenthesis, it will leave you with: $$(24p^{2}-15p)-5(3p^{2}-2p+4)$$ Then distribute the -5 to the second set of parenthesis: $$24p^{2}-15p-15p^{2}+10p-12$$ Then combine like terms to arrive at the final answer: $$9p^{2}-5p-20$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.