## Precalculus (6th Edition)

$$9p^{2}-5p-20$$
First distribute the 3 located outside the first set of parenthesis, it will leave you with: $$(24p^{2}-15p)-5(3p^{2}-2p+4)$$ Then distribute the -5 to the second set of parenthesis: $$24p^{2}-15p-15p^{2}+10p-12$$ Then combine like terms to arrive at the final answer: $$9p^{2}-5p-20$$