Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises - Page 33: 79

Answer

$9q^2+30q+25-p^2$

Work Step by Step

Use the formula $(a+b)(a-b)=a^2-b^2$ and treat $3q+5$ as a single term, we have: $[(3q+5)-p][(3q+5)+p]=(3q+5)^2-p^2=9q^2+30q+25-p^2$
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