#### Answer

$12y^{2}+4$

#### Work Step by Step

First distribute the two located in front of the first set of parenthesis so that you are left with:
$$(24y^{2}-6y+12)-4(3y^{2}-4y+2)$$Then distribute the $-4$ located in front of the second set of parenthesis so that you are left with:
$$24y^{2}-16y+12-12y^{2}+16y-8$$
Then combine like terms (squared with squared, etc.) to get the final answer:
$$12y^{2}+4$$