Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises: 57


$15x^4 - \frac{7}{3}x^3- \frac{2}{9}x^2$

Work Step by Step

$x^2 ( 3x - \frac{2}{3})(5x+ \frac{1}{3}) = x^2 ( 15x^2 - \frac{10}{3}x + x - \frac{2}{9}) = x^2 (15x^2 - \frac{7}{3}x - \frac{2}{9}) = 15x^4 - \frac{7}{3}x^3- \frac{2}{9}x^2$
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