Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises - Page 33: 65

Answer

$16x^4-72x^2+81$

Work Step by Step

Use the formula $(a+b)(a-b)=a^2-b^2$, we have $(2x+3)(2x-3)(4x^2-9)=(4x^2-9)(4x^2-9)=(4x^2-9)^2=16x^4-72x^2+81$
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