Answer
$\{(5z-13,-3z+9,z)\}$
Work Step by Step
1. This system will have unlimited solutions, the second equation gives $y=-3z+9$ and the first equation becomes $x+2(-3z+9)+z=5$ which gives $x=5z-13$
2. The solution set can be expressed as $\{(5z-13,-3z+9,z)\}$
