Chapter 9 - Systems and Matrices - Summary Exercises on Systems of Equations - Exercises - Page 907: 16

$\{(\frac{3}{8},-1)\}$

1. Multiply -3 to the second equation to get $-\frac{3}{x}-\frac{6}{y}=-2$ 2. Add the above to the first equation and get $-\frac{2}{y}=2$, thus $y=-1$ 3. Back substitute to the second equation to get $\frac{1}{x}-2=\frac{2}{3}$, thus $x=\frac{3}{8}$ 4. Thus the solution set is $\{(\frac{3}{8},-1)\}$