Chapter 9 - Systems and Matrices - Summary Exercises on Systems of Equations - Exercises - Page 907: 17

$\{(-1,0,0)\}$

1. Add up the first two equations to get $-8x=8$, thus $x=-1$ 2. From the third equation, we have $-(-1)+6y=1$, thus $y=0$ 3. From the second equation, we have $-3(-1)-2(0)-z=3$, thus $z=0$ 4. Thus the solution set is $\{(-1,0,0)\}$