Answer
$\{(2y+3,y)\}$
Work Step by Step
1. Simplify the first equation (divide by 2) to get $x-2y-3=0$
2. Add the above to the second equation and get $0=0$ which means the system has unlimited solutions.
3. Solve for $x$ from step-1 to get $x=2y+3$
4. Thus the solution set can be written as $\{(2y+3,y)\}$
