Answer
$\{(-\frac{1}{2},-8), (\frac{4}{3},3)\}$
Work Step by Step
1. From the first equation, we have $y=6x-5$
2. Use substitution, the second equation becomes $x(6x-5)=4$ or $6x^2-5x-4=0$
3. Factor the equation to get $(2x+1)(3x-4)=0$, thus $x=-\frac{1}{2}, \frac{4}{3}$
4. Plug the results in the first equation to get $y=-8, 3$
5. Thus the solution set is $\{(-\frac{1}{2},-8), (\frac{4}{3},3)\}$
