Answer
$\{(-3,2)\}$
Work Step by Step
1. Given $\begin{cases} 2x+5y=4 \\ 3x-2y=-13 \end{cases}$ use elimination, multiply 3 to the first and multiply -2 to the second equation, we have $\begin{cases} 6x+15y=12 \\ -6x+4y=26 \end{cases}$
2. Add up the two equations to get $19y=38$, thus $y=2$
3. Use the first equation to get $2x+5(2)=4$, thus $x=-3$
4. Thus the solution set is $\{(-3,2)\}$
