Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 9 - Systems and Matrices - 9.4 Partial Fractions - 9.4 Exercises - Page 895: 7

Answer

$\dfrac{5}{3x}-\dfrac{10}{3(2x+1)} $

Work Step by Step

We will write the partial decomposition as: $\dfrac{5}{3x(2x+1)}=\dfrac{A}{3x}+\dfrac{B}{2x+1} ~~~~(a)$ This implies that $5=A(2x+1)+B (3x)$ Plug $x=0$ to obtain: $A=5$ Now, plug $x=\dfrac{-1}{2}$ to obtain: $B=\dfrac{-10}{3}$ So, the equation (a) becomes: $\dfrac{5}{3x(2x+1)}=\dfrac{5}{3x}-\dfrac{10}{3(2x+1)} $
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