Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - Chapter 8 Test Prep - Review Exercises - Page 841: 88

Answer

$${\text{The graph represents a straight line with slope 2}}$$

Work Step by Step

$$\eqalign{ & r = \frac{2}{{2\cos \theta - \sin \theta }} \cr & {\text{Multiply both sides by }}\frac{1}{r} \cr & 1 = \frac{2}{{2r\cos \theta - r\sin \theta }} \cr & {\text{Where }}{r^2} = {x^2} + {y^2}{\text{ and }}r\cos \theta = x \cr & 1 = \frac{2}{{2x - y}} \cr & 2x - y = 2 \cr & y = 2x - 2 \cr & {\text{Therefore,}} \cr & {\text{The graph represents a straight line with slope 2}} \cr} $$
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