Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - Chapter 8 Test Prep - Review Exercises - Page 841: 83

Answer

$$\left( {2,120^\circ } \right)$$

Work Step by Step

$$\eqalign{ & {\text{Let the rectangular coordinates }}\left( { - 1,\sqrt 3 } \right){\text{ }} \cr & x = - 1{\text{ and }}y = \sqrt 3 \cr & \cr & {\text{Convert to polar coordinates }}\left( {r,\theta } \right) \cr & r = \sqrt {{x^2} + {y^2}} \cr & r = \sqrt {{{\left( { - 1} \right)}^2} + {{\left( {\sqrt 3 } \right)}^2}} \cr & r = 2 \cr & and \cr & \theta = {\tan ^{ - 1}}\left( {\frac{y}{x}} \right) \cr & \theta = {\tan ^{ - 1}}\left( {\frac{{\sqrt 3 }}{{ - 1}}} \right) + 180^\circ \cr & \theta = 120^\circ \cr & \cr & {\text{The polar coordinates are:}} \cr & \left( {2,120^\circ } \right) \cr} $$
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