Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - Chapter 8 Test Prep - Review Exercises - Page 841: 59

Answer

$$ - \frac{1}{2} - \frac{{\sqrt 3 }}{2}i$$

Work Step by Step

$$\eqalign{ & {\left( {\cos {{100}^ \circ } + i\sin {{100}^ \circ }} \right)^6} \cr & {\text{Write in the polar form}} \cr & \cos {100^ \circ } + i\sin {100^ \circ } = 1\angle {100^ \circ } \cr & {\left( {\cos {{100}^ \circ } + i\sin {{100}^ \circ }} \right)^6} = {\left( {1\angle {{100}^ \circ }} \right)^6} \cr & {\text{Solve the power}} \cr & = {\left( 1 \right)^6}\angle 6 \cdot {100^ \circ } \cr & = 1\angle \left( {{{600}^ \circ } - {{360}^ \circ }} \right) \cr & = 1\angle {240^ \circ } \cr & {\text{Write in the rectangular form}} \cr & = \left( {\cos {{240}^ \circ } + i\sin {{240}^ \circ }} \right) \cr & = - \frac{1}{2} + i\left( { - \frac{{\sqrt 3 }}{2}} \right) \cr & = - \frac{1}{2} - \frac{{\sqrt 3 }}{2}i \cr} $$
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