Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - Chapter 8 Test Prep - Review Exercises - Page 841: 67

Answer

$$ - \sqrt 2 - \sqrt 2 i$$

Work Step by Step

$$\eqalign{ & {\text{Trigonometric form }}2\left( {\cos 225^\circ + i\sin 225^\circ } \right) \cr & {\text{Calculate }}\cos 225^\circ {\text{ and }}\sin 225^\circ \cr & \cos 225^\circ = - \frac{{\sqrt 2 }}{2} \cr & \sin 225^\circ = - \frac{{\sqrt 2 }}{2} \cr & {\text{,then}} \cr & 2\left( {\cos 225^\circ + i\sin 225^\circ } \right) = 2\left( { - \frac{{\sqrt 2 }}{2} - \frac{{\sqrt 2 }}{2}i} \right) \cr & = - \sqrt 2 - \sqrt 2 i \cr} $$
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