Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - Chapter 8 Test Prep - Review Exercises - Page 841: 56

Answer

$$ - 2$$

Work Step by Step

$$\eqalign{ & \frac{{4\operatorname{cis} {{270}^ \circ }}}{{2\operatorname{cis} {{90}^ \circ }}} \cr & {\text{Then,}} \cr & = \frac{4}{2}\operatorname{cis} \left( {{{270}^ \circ } - {{90}^ \circ }} \right) \cr & {\text{Simplifying}} \cr & = 2\operatorname{cis} \left( {180} \right) \cr & {\text{Write in the rectangular form}} \cr & = 2\left( {\cos {{180}^ \circ } + i\sin \left( {{{180}^ \circ }} \right)} \right) \cr & = 2\left( { - 1 + i\left( 0 \right)} \right) \cr & = - 2 \cr} $$
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