Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.1 Fundamental Identities - 7.1 Exercises: 77

Answer

$sec^{2}\theta $

Work Step by Step

$\sin ^{2}\left( -\theta \right) +\tan ^{2}\left( -\theta \right) +\cos ^{2}\left( -\theta \right) =1+\tan ^{2}\left( -\theta \right) =\dfrac {1}{\cos ^{2}\left( -\theta \right) }=\dfrac {1}{\cos ^{2}\theta }=sec^{2}\theta $
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.