Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.1 Fundamental Identities - 7.1 Exercises - Page 659: 76

Answer

$-\sin \theta $

Work Step by Step

$\dfrac {\tan \left( -\theta \right) }{sec\theta }=\dfrac {\dfrac {\sin \left( -\theta \right) }{\cos \left( -\theta \right) }}{\dfrac {1}{\cos \theta }}=\dfrac {-\sin \theta }{\dfrac {\cos \theta }{\dfrac {1}{\cos \theta }}}=-\sin \theta $
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.