Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.1 Fundamental Identities - 7.1 Exercises - Page 659: 45


$\dfrac {\pm \sqrt {2x+1}}{x+1}$

Work Step by Step

$\sin \theta =\pm \sqrt {1-\cos ^{2}\theta }=\pm \sqrt {1-\left( \dfrac {x}{x+1}\right) ^{2}}=\pm \sqrt {\dfrac {\left( x+1\right) ^{2}-x^{2}}{\left( x+1\right) ^{2}}}=\pm \dfrac {\sqrt {\left( x+1-x\right) \left( x+1+x\right) }}{\left( x+1\right) }=\dfrac {\pm \sqrt {2x+1}}{x+1}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.