#### Answer

$\tan \theta \sin \theta $

#### Work Step by Step

$sec\theta -\cos \theta =\dfrac {1}{\cos \theta }-\cos \theta =\dfrac {1-\cos ^{2}\theta }{\cos \theta }=\dfrac {\sin ^{2}\theta }{\cos \theta }=\tan \theta \sin \theta $

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$\tan \theta \sin \theta $

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