#### Answer

D

#### Work Step by Step

$1+\sin ^{2}x=\dfrac {\sin ^{2}x}{\sin ^{2}x}+\sin ^{2}x=\dfrac {1-\cos ^{2}x}{\sin ^{2}x}+\sin ^{2}x=csc^{2}x-\cot ^{2}x+\sin ^{2}x\Rightarrow 42\rightarrow D$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

D

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