Answer
$\pm \dfrac {\sqrt {1-\sin ^{2}x}}{\sin x}$
Work Step by Step
$\cot x=\dfrac {\cos x}{\sin x}=\pm \dfrac {\sqrt {1-\sin ^{2}x}}{\sin x}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 7 - Trigonometric Identities and Equations - 7.1 Fundamental Identities - 7.1 Exercises - Page 659: 48
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