#### Answer

$\pm \dfrac {\sqrt {1-\sin ^{2}x}}{\sin x}$

#### Work Step by Step

$\cot x=\dfrac {\cos x}{\sin x}=\pm \dfrac {\sqrt {1-\sin ^{2}x}}{\sin x}$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$\pm \dfrac {\sqrt {1-\sin ^{2}x}}{\sin x}$

$\cot x=\dfrac {\cos x}{\sin x}=\pm \dfrac {\sqrt {1-\sin ^{2}x}}{\sin x}$

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