Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 6 - The Circular Functions and Their Graphs - 6.2 The Unit Circle and Circular Functions - 6.2 Exercises - Page 590: 97

Answer

$8\pi\ m/sec$

Work Step by Step

Given $r=12\ m, \omega=\frac{2\pi}{3}\ rad/sec$, we have $v=r\omega=12\times\frac{2\pi}{3}=8\pi\ m/sec$
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