Answer
$\frac{6}{5}=1.2\ min$
Work Step by Step
Given $\theta=\frac{2\pi}{9}\ rad, \omega=\frac{5\pi}{27}\ rad/min$, we have $t=\frac{\theta}{\omega}=\frac{2\pi}{9}\times\frac{27}{5\pi}=\frac{6}{5}=1.2\ min$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 6 - The Circular Functions and Their Graphs - 6.2 The Unit Circle and Circular Functions - 6.2 Exercises - Page 590: 95
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