Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 6 - The Circular Functions and Their Graphs - 6.2 The Unit Circle and Circular Functions - 6.2 Exercises - Page 590: 113

Answer

$\frac{7\pi}{30}\ cm/min$

Work Step by Step

The minute hand of a clock moves $2\pi$ radians per $60$ minutes, thus $\omega=\frac{2\pi}{60}=\frac{\pi}{30}\ rad/min$ and the linear speed is $v=r\omega=7\times\frac{\pi}{30}=\frac{7\pi}{30}\ cm/min$
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