Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 6 - The Circular Functions and Their Graphs - 6.2 The Unit Circle and Circular Functions - 6.2 Exercises - Page 590: 116

Answer

$1260\pi\ cm/min$

Work Step by Step

The tire moves $2\pi\times35=70\pi$ radians per minute, thus $\omega=70\pi\ rad/min$ and the linear speed is $v=r\omega=18\times70\pi=1260\pi\ cm/min$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.