Answer
$4\ sec$
Work Step by Step
Given $s=\frac{12\pi}{5}\ m, r=\frac{3}{2}\ m, \omega=\frac{2\pi}{5}\ rad/sec$, we have $t=\frac{s}{r\omega}=\frac{\frac{12\pi}{5}}{\frac{3}{2}\times\frac{2\pi}{5}}=4\ sec$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 6 - The Circular Functions and Their Graphs - 6.2 The Unit Circle and Circular Functions - 6.2 Exercises - Page 590: 106
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