Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 6 - The Circular Functions and Their Graphs - 6.2 The Unit Circle and Circular Functions - 6.2 Exercises - Page 590: 114

Answer

$\frac{14\pi}{15}\ mm/sec$

Work Step by Step

The second hand of a clock moves $2\pi$ radians per $60$ seconds, thus $\omega=\frac{2\pi}{60}=\frac{\pi}{30}\ rad/sec$ and the linear speed is $v=r\omega=28\times\frac{\pi}{30}=\frac{14\pi}{15}\ mm/sec$
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