Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions Values and Angle Measures - 5.3 Exercises - Page 532: 54


$a=\dfrac {14\sqrt {3}}{3}$ $m=7\sqrt {3}$ $n=a=\dfrac {14\sqrt {3}}{3};$ $q=\dfrac {14\sqrt {6}}{3}$

Work Step by Step

$a=\dfrac {7}{\sin 60}=\dfrac {7}{\dfrac {\sqrt {3}}{2}}=\dfrac {14}{\sqrt {3}}=\dfrac {14\sqrt {3}}{3}$ $m=7\times \tan 60^{0}=7\sqrt {3}$ $n=a=\dfrac {14\sqrt {3}}{3};$ $q=\dfrac {a}{\sin 45}=\dfrac {\dfrac {14\sqrt {3}}{3}}{\dfrac {\sqrt {2}}{2}}=\dfrac {14\sqrt {6}}{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.