Answer
$a=\dfrac {14\sqrt {3}}{3}$
$m=7\sqrt {3}$
$n=a=\dfrac {14\sqrt {3}}{3};$
$q=\dfrac {14\sqrt {6}}{3}$
Work Step by Step
$a=\dfrac {7}{\sin 60}=\dfrac {7}{\dfrac {\sqrt {3}}{2}}=\dfrac {14}{\sqrt {3}}=\dfrac {14\sqrt {3}}{3}$
$m=7\times \tan 60^{0}=7\sqrt {3}$
$n=a=\dfrac {14\sqrt {3}}{3};$
$q=\dfrac {a}{\sin 45}=\dfrac {\dfrac {14\sqrt {3}}{3}}{\dfrac {\sqrt {2}}{2}}=\dfrac {14\sqrt {6}}{3}$
