Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions Values and Angle Measures - 5.3 Exercises: 34

Answer

$\dfrac {\sqrt {3}}{2}$

Work Step by Step

$\cos 30^{0}=\sqrt {1-\sin ^{2}30}=\sqrt {1-\left( \dfrac {1}{2}\right) ^{2}}=\sqrt {\dfrac {3}{4}}=\dfrac {\sqrt {3}}{2}$
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