Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions Values and Angle Measures - 5.3 Exercises - Page 532: 51

Answer

$y=\dfrac {9}{2};$ $x=\dfrac {9}{2}\sqrt {3};$ $\omega =3\sqrt {3};$ $z=\dfrac {3\sqrt {3}}{2}$

Work Step by Step

$y=9\times \sin 30^{0}=\dfrac {9}{2};$ $x=9\times \cos 30^{0}=\dfrac {9}{2}\sqrt {3};$ $\omega =\dfrac {y}{\sin 60}=\dfrac {\dfrac {9}{2}}{\dfrac {\sqrt {3}}{2}}=3\sqrt {3};$ $z=w\times \cos 60^{\circ }=3\sqrt {3}\times \dfrac {1}{2}=\dfrac {3\sqrt {3}}{2}$
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