Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions Values and Angle Measures - 5.3 Exercises - Page 532: 46

Answer

$\dfrac {2\sqrt {3}}{3}$

Work Step by Step

$csc60^{0}=\dfrac {1}{\sin 60^{0}}=\dfrac {1}{\dfrac {\sqrt {3}}{2}}=\dfrac {2}{\sqrt {3}}=\dfrac {2\sqrt {3}}{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.