Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions Values and Angle Measures - 5.3 Exercises - Page 532: 38


$\sqrt 2$

Work Step by Step

$sec45^{0}=\dfrac {1}{\cos 45^{0}}=\dfrac {1}{\dfrac {\sqrt {2}}{2}}=\dfrac {2}{\sqrt {2}}=\sqrt {2}$
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