Answer
$\sqrt {3}x$
Work Step by Step
Lets assume that equation is
$y=kx+b$ if the line passes through origin $b=0$
$k=\tan \alpha =\tan 60^{0}=\dfrac {\sin 60}{\cos 60}=\dfrac {\dfrac {\sqrt {3}}{2}}{\dfrac {1}{2}}=\sqrt {3}$
$\Rightarrow y=kx=\sqrt {3}x$
