Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions Values and Angle Measures - 5.3 Exercises - Page 532: 48

$\sqrt {3}x$

Work Step by Step

Lets assume that equation is $y=kx+b$ if the line passes through origin $b=0$ $k=\tan \alpha =\tan 60^{0}=\dfrac {\sin 60}{\cos 60}=\dfrac {\dfrac {\sqrt {3}}{2}}{\dfrac {1}{2}}=\sqrt {3}$ $\Rightarrow y=kx=\sqrt {3}x$

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