Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.2 Exponential Functions - 4.2 Exercises - Page 432: 93

Answer

$x=\dfrac {4}{3}$

Work Step by Step

$\left( \sqrt {2}\right) ^{x+4}=4^{x}\Rightarrow 2^{\dfrac {1}{2}\left( x+4\right) }=2^{2x}\Rightarrow \dfrac {1}{2}\left( x+4\right) =2x\Rightarrow \dfrac {3x}{2}=2\Rightarrow x=\dfrac {4}{3}$
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