Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.2 Exponential Functions - 4.2 Exercises - Page 432: 79


$\dfrac {1}{5}$

Work Step by Step

$27^{4x}=9^{x+1}\Rightarrow \left( 3^{3}\right) ^{4x}=\left( 3^{2}\right) ^{x+1}\Rightarrow 3^{12x}=3^{2x+2}\Rightarrow 12x=2x+2\Rightarrow 10x=2\Rightarrow x=\dfrac {2}{10}=\dfrac {1}{5}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.