Answer
$\{-\frac{3}{5} \}$
Work Step by Step
$e^{x-1}=(\frac{1}{e^4})^{x+1}\longrightarrow e^{x-1}=(e^{-4})^{x+1}\longrightarrow e^{x-1}=e^{-4x-4} \longrightarrow x-1=-4x-4 \longrightarrow x=-\frac{3}{5}$ or in set form $\{-\frac{3}{5} \}$
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