#### Answer

$-\dfrac {2}{3}$

#### Work Step by Step

$32^{2x}=16^{x-1}\Rightarrow \left( 25\right) ^{2x}=\left( 2^{4}\right) ^{x-1}\Rightarrow 2^{10x}=2^{4x-4}\Rightarrow 10x=4x-4\Rightarrow 6x=-4\Rightarrow x=-\dfrac {2}{3}$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$-\dfrac {2}{3}$

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