Answer
$\dfrac {1}{2}$
Work Step by Step
$2^{6-3x}=8^{x+1}\Rightarrow 2^{6-3x}=\left( 2^{3}\right) ^{x+1}\Rightarrow 2^{6-3x}=2^{3x+3}\Rightarrow 6-3x=3x+3\Rightarrow 6x=3\Rightarrow x=\dfrac {1}{2}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.2 Exponential Functions - 4.2 Exercises - Page 432: 82
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