Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.2 Exponential Functions - 4.2 Exercises - Page 432: 76

Answer

$0$

Work Step by Step

$5^{2+2x}=25\Rightarrow 5^{2+2x}=5^{2}\Rightarrow 2+2x=2\Rightarrow x=\dfrac {2-2}{2}=0$
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