Precalculus (6th Edition)

$\color{blue}{y=\frac{3}{2}}$
RECALL: (1) The point-slope form of a line's equation is $y-y_1=m(x-x_1)$ where $m$=slope and $(x_1, y_1)$ is a point on the line. (2) The slope-intercept form of a line's equation is $y=mx+b$ where $m$=slope and $(0, b)$ is the line's y-intercept. The given line has a slope of $0$ and a y-intercept of $(0, \frac{3}{2})$. Substitute these into the slope-intercept form in (2) above to obtain: $y=0x+\frac{3}{2} \\\color{blue}{y=\frac{3}{2}}$ This equation cannot be written in slope-intercept form.