#### Answer

slope = $-\frac{2}{3}$
y-intercept: $(0, \frac{16}{3})$
Refer to the graph below.

#### Work Step by Step

Solve for $y$:
$2x+3y=16
\\2x+3y-2x=16-2x
\\3y=-2x+16
\\\frac{3y}{3}=\frac{-2x+16}{3}
\\y=-\frac{2}{3}x+\frac{16}{3}$
This means that the given equation is equivalent to $y=-\frac{2}{3}x+\frac{16}{3}$.
RECALL:
The slope-intercept form of a line's equation is $y=mx+b$ where $m$=slope and $(0, b)$ is the line's y-intercept.
Thus, the equation $y=-\frac{2}{3}x+\frac{16}{3}$ has a slope of $-\frac{2}{3}$ and a y-intercept of $(0, \frac{16}{3})$.
To graph the equation, perform the following steps:
(1) Plot the y-intercept $(0, \frac{16}{3})$.
(2) Use the slope to plot a second point.
Since the slope is $-\frac{2}{3}$, from $(0, \frac{16}{3})$, move 2 units down (the rise) and 3 units to the right (the run) to reach the point $(3, \frac{10}{3})$. Plot $(3. \frac{10}{3})$.
(3) Connect the points using a straight line.
(Refer to the graph in the answer part above)