#### Answer

$\color{blue}{y=\frac{1}{3}x+\frac{7}{3}}$.

#### Work Step by Step

RECALL:
(1) The slope-intercept form of a line's equation is $y=mx+b$ where $m$=slope and $(0, b)$ is the line's y-intercept.
(2) The slope $m$ of a line that contains the points $(x_1, y_2)$ and $(x_2, y_2)$ is given by the formula $m=\dfrac{y_2-y_1}{x_2-x_1}$..
Solve for the slope using the formula in (2) above to obtain:
$m=\dfrac{2-3}{-1-2}=\dfrac{-1}{-3}=\dfrac{1}{3}$
Thus, the tentative equation of the line is $y=\frac{1}{3}x+b$
To find the value of $b$, substitute the x and y values of one of the two given points to obtain:
$y=\frac{1}{3}x+b
\\3=\frac{1}{3}(2)+b
\\3=\frac{2}{3}+b
\\3-\frac{2}{3}=\frac{2}{3}+b-\frac{2}{3}
\\\frac{9}{3}-\frac{2}{3}=b
\\\frac{7}{3}=b$
Therefore, the equation of the line is $\color{blue}{y=\frac{1}{3}x+\frac{7}{3}}$.