# Chapter 2 - Graphs and Functions - 2.5 Equations of Lines and Linear Models - 2.5 Exercises - Page 243: 27

$y-15=5(x-3)$

#### Work Step by Step

RECALL: (1) The point-slope form of a line's equation is $y-y_1=m(x-x_1)$ where $m$=slope and $(x_1, y_1)$ is a point on the line. (2) The slope-intercept form of a line is $y=mx+b$ where $m$=slope and $(0, b)$ is the line's y-intercept. With $m=5$ and $b=15$, substituting these into the slope-intercept form of a line gives: $y=5x+15$ To convert the equation above into point-slope form, subtract 15 to both sides of the equation to obtain: $y-15 = 5x-15$ Factor out $5$ on the right side of the equation to obtain: $y-15=5(x-3)$

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